MOSCOW, March 13 Russian Karen Khachanov lost to American Jenson Brooksby in the second match round of the tennis tournament in American Indian Wells, the prize fund of which is more than 8.5 million dollars. The meeting ended with a score of 6:0, 6:3 in favor of Brooksby. Khachanov had the 25th seed number. The match lasted 1 hour 18 minutes. In the third round, Brooksby will play against the Greek Stefanos Tsitsipas (5th seed). In another match of the game day, the Norwegian Kasper Ruud (8) beat the American Christopher Oybanks. In the next round, he will play against the winner of the match between Argentinean Federico Delbonis (32) and Australian Nick Kyrgios.
